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x^2-45x=-4
We move all terms to the left:
x^2-45x-(-4)=0
We add all the numbers together, and all the variables
x^2-45x+4=0
a = 1; b = -45; c = +4;
Δ = b2-4ac
Δ = -452-4·1·4
Δ = 2009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2009}=\sqrt{49*41}=\sqrt{49}*\sqrt{41}=7\sqrt{41}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-7\sqrt{41}}{2*1}=\frac{45-7\sqrt{41}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+7\sqrt{41}}{2*1}=\frac{45+7\sqrt{41}}{2} $
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